微分方程cosydx+(1+e-x)sinydy=0满足初始条件y x=0=的特

昕玥2019-12-17  29

问题 微分方程cosydx+(1+e-x)sinydy=0满足初始条件y x=0=的特解是:(A)cosy=(1+ex) (B)cosy=(1+ex) (C)cosy=4(1+ex) (D)cos2y=(1+ex)

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答案A

解析此为可分离变量的方程,将变量分离得[img]/upload/tiku/190/2460263_1.jpg[/img][img]/upload/tiku/190/2460263_1_1.jpg[/img]-tan ydy,两边积分,[img]/upload/tiku/190/2460263_1_2.jpg[/img][img]/upload/tiku/190/2460263_1_3.jpg[/img]-[img]/upload/tiku/190/2460263_1_4.jpg[/img]tan ydy,[img]/upload/tiku/190/2460263_1_5.jpg[/img]
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