13,115,135,( )A.165;B.175;C.1125;D.163

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问题 13,115,135,( )

选项 A.165;B.175;C.1125;D.163

答案D

解析每项分解=>(1,3),(1,15),(1,35),(1,63)=>可视为1,1,1,1,1和3,15,35,63的组合,对于1,1,1,1,1 等差;对于3,15,35,63.3=1×3,15=3×5,35=5×7,63=7×9每项都等于两个连续的奇数的乘积(1,3,5,7,9).
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