线全长为620m,纵横坐标增量闭合差分别为fx=0.12m,fy=-0.16m,

tikufree2019-12-17  24

问题 线全长为620m,纵横坐标增量闭合差分别为fx=0.12m,fy=-0.16m,则导线全长相  对闭合差为    (    )

选项 A.1/2200 B.1/3100C.1/4500D.1/15500

答案B

解析导线全长相对闭合差的计算公式为K=[img]/upload/tiku/337/6868143_1.png[/img]
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