曲面z=1-x2-y2在点(1/2，1/2，1/2)处的切平面方程是:

恬恬2019-12-17 13

问题曲面z=1-x2-y2在点(1/2，1/2，1/2)处的切平面方程是:

选项 A.x+y+z-3/2=0B.x-y-z+3/2=0C.x-y+z-3/2=0D.x-y+z+3/2=0

答案A

解析提示 F(x,y,z)=x2+y2+z-1[img]/upload/tiku/233/2658611_1.jpg[/img]

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