曲面z=1-x2-y2在点(1/2,1/2,1/2)处的切平面方程是: A.x

恬恬2019-12-17  21

问题 曲面z=1-x2-y2在点(1/2,1/2,1/2)处的切平面方程是:A.x+y+z-3/2=0 B.x-y-z+3/2=0 C.x-y+z-3/2=0 D.x-y+z+3/2=0

选项

答案A

解析提示:F(x,y,z)=x2+y2+z-1[img]/upload/tiku/190/2457217_1.jpg[/img]
转载请注明原文地址:https://ti.zuoweng.com/ti/nPSNKKKQ